IS: ‘Use Regular Expression” and “Replace All” with a find string “, “ {note the trailing space after the comma}
And a replace string of “\n, xyz.”
Editor text is:
SELECT Columnname1, Columnname2, Columnname3, Columnname4, Columnname5, Columnname6, Columnname7
FROM TableName
Results like:
, xyz. Columnname2 <- notice the space between the ‘xyz.’ and the ‘Columnname2’.
Should Be:
, xyz.Columnname2 <- notice no space between the ‘.’ and ‘C’.
Hope this is helpfull